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eha

12:56
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  1. n,f,a[99999],m=1e4;
  2. p(x){a[x]=x*2+5,a[x+1]=x+4,x<m&&p(x+2);}
  3. r(){~scanf("%d%d",&n,&f)&&(s(n),r(printf("%d\n",f)));}
  4. s(x){x&&f>=m&&(f%=m,x--),x&&(f=a[f]),--x>0&&s(x);}
  5. main(){scanf("%*d"),p(0),r();}
  6.  


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